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An empty 2,500 kg train car is headed northbound at a velocity of 5 m/s. Ahead of the first car, an empty 1,500 kg car is headed northbound on the same track at 1 m/s. The faster train bumps into the slower one, and they combine into one train. What is the velocity of the two-car train? 1 m/s 3 m/s 3. 5 m/s 5 m/s.

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asuwafohjames

The velocity of the two-car train is 3.5 m/s.

To solve the problem above, we use the law of conservation of momentum

Law of conservation of momentum: States that, for a closed system, the total momentum before collision is equal to the total momentum after collision.

⇒ Formula:

mu+m'u' = V(m+m')..................... Equation 1

⇒ Where:

  • m = mass of the faster train
  • m' = mass of the slower train
  • u = initial velocity of the faster train
  • u' = initial velocity of the slower train
  • V = common velocity of the two trains

⇒ make V the subject of the equation

  • V = (mu+m'u')/(m+m')....................... Equation 2

From the question,

⇒ Given:

  • m = 2500 kg
  • m' = 1500 kg
  • u = 5 m/s
  • u' = 1 m/s

⇒ Substitute these values into equation 2

  • V = [(2500×5)+(1500×1)]/(2500+1500)
  • V = [12500+1500]/(4000)
  • V = 14000/4000
  • V = 3.5 m/s.

Hence, The velocity of the two-car train is 3.5 m/s

Learn more about the law of conservation of momentum: https://brainly.com/question/9408577

Answer:

3.5

Explanation:

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