The number of time it take the twirler’s baton to complete one spin is 0.56 seconds
Given the following data:
Radius = [tex]\frac{0.76}{2}[/tex] = 0.38 m.
To determine the number of time it take the twirler’s baton to complete one spin:
Mathematically, the centripetal acceleration for the twirler’s baton is given by this formula:
[tex]A = \frac{4\pi^2 r}{t^2}[/tex]
Where:
Making t the subject of formula, we have:
[tex]t =\sqrt{\frac{4\pi^2 r}{A}}[/tex]
Substituting the parameters into the formula, we have;
[tex]t =\sqrt{\frac{4(3.142)^2 \times 0.38}{47.8}}\\\\t =\sqrt{\frac{39.489 \times 0.38}{47.8}}\\\\t =\sqrt{\frac{15.0058}{47.8}}[/tex]
Time, t = 0.56 seconds
Read more on centripetal acceleration here: https://brainly.com/question/2788500
