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An object was measured by a worker as
17.400 cm long, however, the manufacturer
specifications list the length of the object
at 17.900 cm. What is the percent error in
the worker's measurement?
a. 2.79% or b. 2.87%

Respuesta :

Answer:

2.79 % error

Explanation:

Percent Error = 100 x [(Actual - Measured) / Actual]

Percent Error = 100 x [(17.900 - 14.700) / 17.900]

Percent Error = 100 x [0.5 / 17.900]

Percent Error = 100 x 0.02793

Percent Error = 2.7932 % or 2.79 %

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