Answer:
Let O be the center of a circle whose radius is r cm , in which AB= 14 cm long
cord is at a distanceof 24 cm from O. Draw a perpendicular OD on AB , thus ,
OD= 24 cm.
In right angled triangle. ODB
OB^2 = OD^2+ DB^2
r^2 =(24)^2+(AB/2)^2 = 576+(14/2)^2
r^2 = 576+ 49=625
r = √625. =25 cm. Answer.
