PrOblem 1: Find the slope of the line containing the points: (3,-5) and (-1, -2)
Problem 2: Find the x and y intercepts of the line: 2x – 3y = 12
Problem 3: Graph the line x-4y=8

Respuesta :

Answer:

1) -3/4

2) (6, 0), (0, -4)

3) connect (0,-2) and (8,0) together

Step-by-step explanation:

1) (-2) - (-5) / (-1) - 3 = -3/4

2) x = 0 -3y=12 y = -4, y= 0 2x =  12 x = 6, x intercept = (6, 0) y intercept = (0, -4)

3) x - 4y = 8 this could be written as y = x/4 - 2 and y intercept is (0, -2) and x intercept is (8, 0) so connect these points together and make a line

#1

  • m=y2-y1/x2-x1
  • m=-2+5/-1-3
  • m=3/-4

#2

Inetercept form x/a+y/b=1

  • 2x-3y=12
  • 2/12x-3/12y=12/12
  • x/6-y/4=1

x inetercept at 6 and y intercect at -4

#3

Graph attached

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