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Three children each contributed toward a birthday present for their mother. The oldest contributed three times as much as the youngest, while the second oldest contributed 50 cents more than the youngest. If the present costs $10.50, how much did each contribute?

Respuesta :

Answer:

Youngest child: $2

oldest child: $6

Second oldest: $2.50

Step-by-step explanation:

Youngest child= x

oldest child= 3x

Second oldest: .50+x

x+3x+.50+x=10.5

5x+.50=10.5

    - .50= - .50

5x=10

divided both numbers by 5 and x is equal to 2. So, the youngest child is $2 and you add .50, which is $2.50, and thats for the second child. Last, you do 2 times 3 equals $6 which is the oldest child.

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