The charge of the electrons is [tex]8.02 \times 10^{-19} \ C[/tex].
The given parameters:
The angular speed of the electron is calculated as follows;
[tex]\omega = 2\pi N\\\\\omega = 2\pi \ \frac{rad}{1 \ rev} \times 1.4 \times 10^6 \ rev/s\\\\\omega = 8.798 \times 10^6 \ rad/s[/tex]
The charge of the electrons is calculated as follows;
[tex]F_c= m\omega ^2 r\\\\F_{B}= qvB = q\omega r B \\\\F_c = F_B\\\\m\omega ^2 r = q\omega r B \\\\q = \frac{m\omega ^2 r}{\omega r B} \\\\q = \frac{m \omega }{B} \\\\q = \frac{9.11 \times 10^{-31} \times 8.798 \times 10^6}{10^{-5}} \\\\q = 8.02 \times 10^{-19} \ C[/tex]
The charge of the electrons is [tex]8.02 \times 10^{-19} \ C[/tex].
The complete question here:
Electrons execute 1.4*10^6 revolutions per sec in a magnetic field of flux density 10⁻⁵ T. What will be the value of charge of the electron?
Learn more about magnetic force of electrons here: https://brainly.com/question/3990732
