General method:
Given numbers are 2.23 bar and 2.24 bar
- 2.23 bar = 2.232323...
- 2.24 bar = 2.242424...
Two rational numbers between them
= 2.232525... and 2.239899...
Mean Method:
Let X = 2.232323...→ → →eqn(i)
since the periodicity is 2 then multiply eqn(i) with 100
⇛100×X = 2.232323...×100
⇛100X = 223.232323...→ → →eqn(ii)
Subtract eqn(ii)- eqn(i)
100X = 223.232323...
X = 2.232323...
(-)
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99X = 221.000000...
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⇛99X = 221
⇛X = 221/99
and
Let X = 2.242424...→ → →eqn(i)
since the periodicity is 2 then multiply eqn(i) with 100
⇛100×X = 2.242424...×10
⇛100X = 224.242424...→ → →eqn(ii)
Subtract eqn(ii)- eqn(i)
100X = 224.242424...
X = 2.242424...
(-)
_________________
99X = 222.000000
_________________
⇛92X = 222
⇛X = 222/99
Now we have 221/99 and 222/99
The rational number between them by mean method (a+b)/2
⇛{(221/99)+(222/99)}/2
⇛(443/99)/2
⇛443/198
and Second rational number
⇛{(221/99)+(443/198)}/2
⇛{(442+443)/198}/2
⇛(885/198)/2
⇛885/396
Answer: The two rational numbers between them are 443/198 and 885/396.
also read similar questions: Give five rational numbers lying between 3/5 and 4/5. Insert six rational numbers between 3 and 4.
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