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10. Find three consecutive even integers such that the product of the first and the second is 92 more
than twice the third integer.

Respuesta :

Answer:

  10, 12, 14  or  -10, -8, -6

Step-by-step explanation:

We can let x represent the middle integer. Then the smaller one is x-2 and the larger one is x+2. The given relation is ...

  (x-2)(x) = 92 +2(x+2)

  x^2 -2x = 92 +2x +4 . . . eliminate parentheses

  x^2 -4x = 96 . . . . . . . . . subtract 2x

  x^2 -4x +4 = 100 . . . . . . add 4 to complete the square

  (x -2) = ±√100 = ±10 . . . take the square root

  x = 2 ± 10 = -8 or +12 . . . . add 2

The three integers might be ...

  -10, -8, -6  or  10, 12, 14