Using the normal distribution, it is found that the area of the shaded region is of 0.7823.
In a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
In this problem:
The shaded region is the region to the left of 64.2, hence it's area is the p-value of Z when X = 64.2.
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{64.2 - 59}{6.7}[/tex]
[tex]Z = 0.7761[/tex]
[tex]Z = 0.7761[/tex] has a p-value of 0.7823.
The area of the shaded region is of 0.7823.
To learn more about the normal distribution, you can take a look at https://brainly.com/question/24663213