Answer:
75%
Explanation:
So, the reaction will consume 1 mole of hydrogen gas and produce
1mole H2⋅2 moles NH33moles H2=0.667 moles NH3
at 100% yield. This represents the reaction's theoretical yield.
Now, you know that the reaction produced 0.50 moles of ammonia. This represents the reaction's actual yield.
In order to find the percent yield, you need to figure out how many moles of ammonia are actually produced for every 100 moles of ammonia that could theoretically be produced.
You know that 0.667 moles will produce 0.50 moles, so you can say that
100moles NH3.in theory⋅0.50 moles NH3.actual0.667moles NH3.in theory=75 moles NH3.actual
Therefore, you can say that the reaction has a percent yield equal to
% yield = 75%
