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The lab stockroom has a bottle of Sulfuric acid labeled 15.5M. How many mL of water will you need to add to 5.41mL of the acid solution in order to get a concentration of 0.175M?

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Eduard22sly

The volume of water needed to make the solution is 473.76 mL

We'll begin by calculating the volume of the diluted solution.

  • Molarity of stock solution (M₁) = 15.5 M
  • Volume of stock solution needed (V₁) = 5.41 mL
  • Molarity of diluted solution (M₂) = 0.175 M
  • Volume of diluted solution (V₂) =?

M₁V₁ = M₂V₂

15.5 × 5.41 = 0.175 × V₂

83.855 = 0.175 × V₂

Divide both side by 0.175

V₂ = 83.855 / 0.175

V₂ = 479.17 mL

Finally, we shall determine the volume of water needed.

  • Volume of stock solution needed (V₁) = 5.41 mL
  • Volume of diluted solution (V₂) = 479.17 mL
  • Volume of water =?

Volume of water = V₂ – V₁

Volume of water = 479.17 – 5.41

Volume of water = 473.76 mL

Therefore, the volume of the water needed is 473.76 mL

Learn more about dilution: https://brainly.com/question/16167657

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