0944399 0944399

13-12-2021
Mathematics

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Solve the equation for z, where z is restricted to the given interval.

[tex]y=7sinz[/tex], for z in [tex][-\frac{\pi }{2}, \frac{\pi }{2} ][/tex]

Respuesta :

jdoe0001 jdoe0001

13-12-2021

[tex]y = 7sin(z)\implies 0 = 7sin(z)\implies 0=sin(z)\implies sin^{-1}(0)=sin^{-1}[sin(z)] \\\\\\ sin^{-1}(0)=z\implies 0=z[/tex]

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