Marla was given the point (1, 3), (2, 1), and (-2, -15). She was asked to find a quadratic function that fit these 3 given points. Marla created a system of three equations with three variables to solve the problem and then used the matrix functions on her graphing calculator to find the equation. Which equation can be written given these 3 points?

Respuesta :

The quadratic equation is given by y = -2x² + 4x + 1

The standard form of a quadratic equation is given by:

y = ax² + bx + c

At point (1, 3):

3 = a(1)² + b(1) + c

a + b + c = 3      (1)

At point (2, 1):

1 = a(2)² + b(2) + c

4a + 2b + c = 1      (2)

At point (-2, -15):

-15 = a(-2)² + b(-2) + c

4a - 2b + c = -15      (3)

Solving equations 1, 2 and 3 simultaneously gives:

a = -2, b = 4, c = 1

The quadratic equation is given by y = -2x² + 4x + 1

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