What is the equation for the line perpendicular to y=3/2x + 2 that contains (3, -5)?
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Answer:
y=-2/3x-3
Step-by-step explanation:
let the slope of the given line =m1
let the slope of the perpendicular line,=m2
m2=-1/m1
m2=-1/3/2
m2=-2/3
Now the equation of the perpendicular line
y--5=-2/3(x-3)
y+5=-2/3(x-3)
3y+15=-2x+6
3y=-2x+6-15
3y=-2x-9
y=-2/3x-3