The segments on triangle HJK are illustrations of equivalent ratios
The length of line AJ is 8.75 inches
The given parameters are:
[tex]H A = 5.25[/tex]
[tex]HB = 3[/tex]
[tex]BK = 5[/tex]
Because lines AB and JK are parallel lines, then we have the following equivalent ratios
[tex]HA:HB = AJ:BK[/tex]
Substitute values for length HA, HB and BK.
[tex]5.25:3 = AJ:5[/tex]
Express both ratios as fractions
[tex]\frac{5.25}{3} = \frac{AJ}5[/tex]
Multiply both sides by 5
[tex]\frac{5.25}{3} \times 5= AJ[/tex]
[tex]8.75= AJ[/tex]
Rewrite as:
[tex]AJ = 8.75[/tex]
Hence, the length of line AJ is 8.75 inches
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