The chemical equation below shows the decomposition of ammonium nitrate (NH4NO3). NH4NO3 Right arrow. N2O 2H2O A chemist who is performing this reaction starts with 160. 1 g of NH4NO3. The molar mass of NH4NO3 is 80. 03 g/mol; the molar mass of water (H2O) is 18. 01 g/mol. What mass, in grams, of H2O is produced? 9. 01 18. 01 36. 03 72. 6.

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Eduard22sly Eduard22sly · Answer 1 · 2021-12-15T11:17:10+01:00

The mass of water, H₂O produced from the reaction is 72.06 g

We'll begin by calculating the mass of NH₄NO₃ that reacted and the mass of H₂O produced from the balanced equation.

NH₄NO₃ —> N₂O + 2H₂O

Molar mass of NH₄NO₃ = 80.03 g/mol

Mass of NH₄NO₃ from the balanced equation = 1 × 80.03 = 80.03 g

Molar mass of H₂O = 18.01 g/mol

Mass of H₂O from the balanced equation = 2 × 18.01 = 36.02 g

From the balanced equation above,

80.03 g of NH₄NO₃ reacted to produce 36.02 g of H₂O

Finally, we shall determine the mass of H₂O produced by the reaction of 160.1 g of NH₄NO₃.

From the balanced equation above,

80.03 g of NH₄NO₃ reacted to produce 36.02 g of H₂O.

Therefore,

160.1 g of NH₄NO₃ will react to produce = (160.1 × 36.02) / 80.03 = 72.06 g of H₂O.

Thus, the mass of water, H₂O produced from the reaction is 72.06 g

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