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Two spherical balloons are filled with water. The first balloon has a radius of 3 cm, and the second has a radius of 6 cm. How much greater is the volume of water in the larger balloon than in the smaller balloon? Use 3. 14 to approximate pi. Round to the nearest hundredth if necessary. Enter your answer as a decimal in the box.

Respuesta :

Answer:

V = 4/3 R^3

V2 / V1 = (R2 / R1)^3 = 2^3 = 8

8.00

Eduard22sly

The volume of water in the larger balloon is 8 times greater than in the smaller balloon

We'll begin by calculating the volume of each balloon.

For smaller balloon:

  • Radius (r) = 3 cm
  • Pi (π) = 3.14
  • Volume (V) =?

V = 4/3 πr³

V = 4/3 × 3.14 × 3³

V = 113.04 cm³

For larger balloon:

  • Radius (r) = 6 cm
  • Pi (π) = 3.14
  • Volume (V) =?

V = 4/3 πr³

V = 4/3 × 3.14 × 6³

V = 904.32 cm³

Finally, we shall determine how much greater the larger balloon is to the smaller balloon

  • Volume of smaller balloon = 113.04 cm³
  • Volume of larger balloon = 904.32 cm³
  • Greatness =?

Greatness => large / small

Large / small = 904.32 / 113.04

Large / small = 8

Cross multiply

Large = 8 × small

Therefore, the larger balloon is 8 times greater than the smaller balloon.

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