Line ST and point V are shown on the graph. On a coordinate plane, line S T goes through (negative 5, 0) and (5, 2). Point V is at (0, negative 2). Line VW is to be drawn on the graph such that it is perpendicular to line ST. If the coordinates of point W are (â’1, y), what is the value of y? â’7 â’5 2 3.

Respuesta :

The value of y in the coordinates of point W is 3

The points are given as:

[tex]S = (-5,0)[/tex]

[tex]T = (5,2)[/tex]

[tex]V = (0,-2)[/tex]

[tex]W = (-1,y)[/tex]

Start by calculating the slope of line ST

[tex]m=\frac{y_2 - y_1}{x_2 -x_1}[/tex]

So, we have:

[tex]m=\frac{2- 0}{5--5}[/tex]

[tex]m=\frac{2}{10}[/tex]

[tex]m=\frac{1}{5}[/tex]

Next, calculate the slope of line VW

[tex]m=\frac{y_2 - y_1}{x_2 -x_1}[/tex]

So, we have:

[tex]m = \frac{y --2}{-1-0}[/tex]

[tex]m = \frac{y +2}{-1}[/tex]

[tex]m = -y -2[/tex]

Since both lines are perpendicular, then the product of the slopes is -1.

So, we have:

[tex]\frac 15 \times (-y -2) = -1[/tex]

Divide both sides by -5

[tex]y +2 = 5[/tex]

Subtract 2 from both sides

[tex]y = 3[/tex]

Hence, the value of y in the coordinates of point W is 3

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