- A right isosceles triangle has legs that are each 10 mm.
- Here, base (b) = 10 mm
- Height (h) = 10 mm
- Let the length of the hypotenuse be x.
- Therefore, in the right triangle
[tex](b) ^{2} + {(h)}^{2} = {(x)}^{2} \: \: \: ( by \: \: \: pythagoras \: \: \: theorem)\\ = > {(10)}^{2} + {(10)}^{2} = {(x)}^{2} \\ = > 100 + 100 = {x}^{2} \\ = > 200 = {x}^{2} \\ = > x = \sqrt{200} mm \\ = > x = \sqrt{2 \times 2 \times 2 \times 5 \times 5}mm \\ = > x = 2 \times 5 \sqrt{2} mm \\ = > x = 10 \sqrt{2} mm[/tex]
- So, the length of the hypotenuse is 10√2 mm.
Answer:
10√2 mm.
Hope you could get an idea from here.
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