The molecular formula of the compound is C6H12O6.
1) We know that;
1 mole of CO2 contains 6.02 X 10^23 atoms
x moles of CO2 contains 1.5 X 10^23 atoms
x = 1 mole X 1.5 X 10^23 atoms /6.02 X 10^23 atoms
x = 0.25 moles of CO2
2) 1 mole of pure Al has 27 g
x moles of Al has 5 g
x = 1 mole × 5 g/ 27 g
x = 0.19 moles
If 1 mole of Al contains 6.02 X 10^23 atoms
0.19 moles of Al contains 0.19 moles × 6.02 X 10^23 atoms /1 mole
= 1.14 X 10^23 atoms
3) From 2Na + Cl2 ---> 2NaCl;
2 moles of Na produces 2 moles of NaCl hence 3 moles of Na will also produce 3 moles of NaCl.
4) The molar mass of K2SO4 is obtained from;
2(39) + 32 + 4(16) = 78 + 32 + 64 = 174 g/mol
Now;
Percentage by mass of K = 2(39)/ 174 × 100/1 = 44.8%
Percentage by mass of S = 32/174 × 100/1 = 18.4%
Percentage by mass of O = 4(16)/174 × 100/1 = 36.8%
5) The reaction equation is;
4Al(s) + 3O2(g) ----> 2Al2O3
Total mass present = 162g + 144g = 306 g
Mass percent of Al = 162g/ 306 g × 100/1 =52.9%
6)
C - 40/12 H - 6.71/1 O - 53.29/16
C - 3.33 H - 6.71 O - 3.33
Dividing through by the lowest ratio
C- 3.33/3.33 H - 6.71/3.33 O - 3.33/3.33
C - 1 H - 2 O - 1
The empirical formula is CH2O
Now;
[12 + 2(1) + 16] n = 180.16
30n = 180.16
n = 180.16/30
n = 6
The molecular formula is C6H12O6.
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