Respuesta :

We are given –

  • Area of rectangular is = 92 square mm
  • Length of rectangular is = 11.5 mm

  • We are asked to find out the value of perimeter of the rectangular! Let's find it's breadth first!

We know that–

[tex]\qquad[/tex][tex] \purple{\bf\longrightarrow Area_{(Rectangular)} = Length \times Breadth} [/tex]

[tex]\qquad[/tex][tex] \sf \longrightarrow 92 = 11.5 \times Breadth [/tex]

[tex]\qquad[/tex][tex] \sf \longrightarrow Breadth = \cancel{\dfrac{92}{11.5}}[/tex]

[tex]\qquad[/tex][tex] \purple{\bf \longrightarrow Breadth = 8 \: mm}[/tex]

Now, Perimeter of rectangular –

[tex]\qquad[/tex][tex] \pink{\bf \longrightarrow Perimeter _{(Rectangular) } = 2( Length + Breadth) }[/tex]

[tex]\qquad[/tex][tex] \sf \longrightarrow Perimeter _{(Rectangular) }= 2( 11.5 +8) [/tex]

[tex]\qquad[/tex][tex] \sf \longrightarrow Perimeter _{(Rectangular) } = 2 \times 19.5[/tex]

[tex]\qquad[/tex][tex]\pink{ \bf \longrightarrow Perimeter _{(Rectangular) } = 39\: mm}[/tex]

  • Henceforth, Perimeter of rectangular is 39mm.

_______________________________________

TheAmethyst

Answer:

  • Perimeter = 39 mm

Step-by-step explanation:

In this question we are given with ,

  • Area of rectangle = 92 sq mm

  • Length of rectangle = 11.5 mm

And we're asked to find the perimeter of rectangle .

Solution : -

We know that ,

[tex] \pink{ \boxed{\sf{Area \: of \: rectangle = L × W}}}[/tex]

Where ,

  • L = length of rectangle

  • W = width of rectangle

So from this formula we can find the width of rectangle and equating it with 92 ( because 92 is the given area ) . Substituting value of length :

[tex] \longmapsto \: 11.5 \times W = 92[/tex]

Step 1 : Multiplying 11.5 and W :

[tex] \longmapsto \: 11.5W = 92[/tex]

Step 2 : Dividing by 11.5 on both side :

[tex] \longmapsto \: \frac{ \cancel{11.5}W}{ \cancel{ 11.5}} = \frac{92}{11.5} [/tex]

On further calculations we get :

[tex] \longmapsto \: W = \cancel{\frac{920}{115} }[/tex]

Step 3 : By cancelling 920 by 115 we get :

[tex] \longmapsto \: \purple{\boxed{ \bold{W = 8 \: mm}}}[/tex]

  • Therefore , width of rectangle is 8 mm .

Finding Perimeter :

We know that ,

[tex] \blue{ \boxed{ \sf{Perimeter \: of \: rectangle = 2 ( L +W )}}}[/tex]

Where ,

  • L = Length of rectangle

  • W = Width of rectangle

Substituting values in formula :

[tex] \longrightarrow \: 2(11.5 + 8)[/tex]

Step 1 : Solving parenthesis :

[tex] \longrightarrow \: 2(19.5)[/tex]

Step 2 : Multiplying 2 with 19.5 :

[tex] \longrightarrow \: \green{\boxed{ \bold{39 \: mm}}}[/tex]

  • Therefore, perimeter of rectangle is 39 mm.

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