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Some information about a direct variation is given in the table below. If the equation
of this direct variation is y = kx , find the coefficient k and fill in the missing
information.

Some information about a direct variation is given in the table below If the equation of this direct variation is y kx find the coefficient k and fill in the mi class=

Respuesta :

xenia168

Answer:

Step-by-step explanation:

y = kx ;

k = [tex]\frac{y}{x}[/tex] ; x = [tex]\frac{y}{k}[/tex]

~~~~~~~~~~~~~

k = [tex]\frac{1}{2}[/tex] ÷ 1 = [tex]\frac{1}{2}[/tex]

[tex]y_{1}[/tex] = [tex]\frac{1}{2}[/tex] × ( - 8 ) = - 4

[tex]y_{2}[/tex] = [tex]\frac{1}{2}[/tex] × ( - 4 ) = - 2

[tex]y_{3}[/tex] = [tex]\frac{1}{2}[/tex] × 2 = 1

[tex]x_{5}[/tex] = [tex]\frac{1}{3}[/tex] ÷ [tex]\frac{1}{2}[/tex] = [tex]\frac{2}{3}[/tex]

[tex]x_{6}[/tex] = - [tex]\frac{1}{4}[/tex] ÷ [tex]\frac{1}{2}[/tex] = - [tex]\frac{1}{2}[/tex]

[tex]x_{7}[/tex] = 0

( x , y ) : ( - 8 , - 4 ), ( - 4 , - 2 ), ( 2 , 1 ), ( 1 , [tex]\frac{1}{2}[/tex] ), ( [tex]\frac{2}{3}[/tex] , [tex]\frac{1}{3}[/tex] ), ( - [tex]\frac{1}{2}[/tex] , - [tex]\frac{1}{4}[/tex] ), ( 0 , 0 )

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