Easy question, Worth 80 points, PLEASE HELP!! What are the angles and the side measurements for this triangle?
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Answer:
the angles are 89.2°, 34.5°, 56.3° and the sides are √26units, √8units, √18units respectively
Step-by-step explanation:
Distance between points (2,5) and (-1,2)
Using the formula, √(X2 - X1)² + (Y2 - Y1)²
= √(-1-2)²+(2-5)²
=√(-3)²+(-3)²
=√9+9
=√18 or 3√2
Distance between points (-1,2) and (4,3)
=√[4-(-1)]²+(3-2)²
= √5²+1²
=√25+1
=√26
Distance between points (2,5) and (4,3)
=√(4-2)²+(3-5)²
=√2²+(-2)²
=√4+4
=√8
Using Cosine rule/formula, C²= A²+B²-2abcosc
Let C be √18, A be √26 and B be √8
√18²=√26²+√8² - 2√26.√8cosc
18= 26+8 - 2√208cosc
18= 34 -2√208cosc
2√208cosc= 34-18
Cosc = 16/2√208
Cosc= 0.5546
c= Cos`¹(0.5547)
c= 56.3°
Using sine rule/formula
Sinc/C= Sina/A=Sinb/B
Sin56.3/√18= Sina/√26
Sina= (0.8320 × √26)/ √18
Sina= 0.9999
a= Sin`¹(0.9999)
a= 89.2
56.3+89.2+b= 180°( sum of angles in a triangle)
145.5 + b =180
b=180-145.5
b= 34.5