0944399
contestada

Solve the equation for solutions over the interval ​[0​°, 360°​).
[tex]tan^{2}x + 7 tanx +8 =0[/tex]

Respuesta :

Answer:

[tex]x=98.13^\circ,135^\circ,278.13^\circ,315^\circ[/tex]

Step-by-step explanation:

[tex]tan^2x+7tanx+8=0,[0^{\circ},360^\circ)[/tex]

[tex]tan^2x+7tanx+8=0[/tex]

[tex]u=tanx[/tex] <-- U-substitution

[tex]u^2+7u+8=0[/tex]

[tex](u+7)(u+1)=0[/tex]

[tex](tanx+7)(tanx+1)=0[/tex] <-- Replace u with tanx

[tex]tanx+7=0[/tex]

[tex]tanx=-7[/tex]

[tex]x=98.13^\circ,278.13^\circ[/tex]

[tex]tanx+1=0[/tex]

[tex]tanx=-1[/tex]

[tex]x=135^\circ,315^\circ[/tex]

Therefore, [tex]x=98.13^\circ,135^\circ,278.13^\circ,315^\circ[/tex]