If a rocket experiences an acceleration generated by the gravity force between the earth and itself, what is this acceleration if the rocket flies 1000 km above the ground and the Earth's radius is 6.378 * 10 ^ 6 * r m. We know the Earth has a mass of 5.97*10^ 24 kg(in m/s^ 2 , G=6.67*10^ -11 N(m/kg)^ 2 ) ?
a 8.97
b 7.32
c 9.81
d 5.5
e 11.45

Respuesta :

This question involves the concepts of Gravitational Force and Weight force.

The value of acceleration is "b. 7.32 m/s²".

At the given height the weight of the rocket must be equal to the gravitational force between rocket and the Earth:

[tex]W=F_G\\mg=\frac{GmM}{R^2}\\\\g=\frac{GM}{R^2}[/tex]

where,

g = acceleration = ?

G = universal gravitational constant = 6.67 x 10⁻¹¹ N.m²/kg²

M = mass of earth = 5.97 x 10²⁴ kg

R = Radius of Earth + Height = 6.378 x 10⁶ m + 1 x 10⁶ m = 7.378 x 10⁶ m

Therefore,

[tex]g=\frac{(6.67\ x\ 10^{-11}\ N.m^2/kg^2)(5.97\ x\ 10^{24}\ kg)}{(7.378\ x\ 10^6\ m)^2}[/tex]

g = 7.32 m/s²

Learn more about the gravitational force here:

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