Four tour buses depart the terminal on the same day. The itinerary of the first bus takes 6 days, for the second bus it takes 8 days, for the third bus it takes 10 days, and the fourth bus takes 15 days. Assuming that another tour begins the same day that the bus returns to the terminal, how many days will it take until all four buses return to the terminal on the same day?

Respuesta :

Using the least common factor, it is found that it will take 120 days until all four buses return to the terminal on the same day.

  • Considering their itineraries, the number of days it will take until all four buses return to the terminal on the same day is the lcm of 6, 8, 10 and 15.

To find their least common factor, we factor each number by prime numbers, hence:

6 - 8 - 10 - 15|2

3 - 4 - 5 - 15|2

3 - 2 - 5 - 15|2

3 - 1 - 5 - 15|3

1 - 1 - 5 - 5|5

1 - 1 - 1 - 1

Hence, lcm(6, 8, 10, 15) = 2³ x 3 x 5 = 8 x 15 = 120.

It will take 120 days until all four buses return to the terminal on the same day.

To learn more about the least common factor, you can take a look at https://brainly.com/question/24873870