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a ball of mass 0.15 kg is attached to one end of a string 1.10 m long. the ball moves in a horizontal circle with a speed of 12 m/s. determine the magnitude of the tension in the string​

Respuesta :

Paounn

Answer:

[tex]19.64N[/tex]

Explanation:

Let's remember that if a mass describes a circle of radius [tex]l[/tex] with a constant speed of [tex]v[/tex], it has an angular velocity [tex]\omega=\frac vl[/tex]. in our case, our angular velocity will be of [tex]12/1.1= 10.91 rad/s[/tex].

Now that same mass will be subject of a centripetal acceleration [tex]a_c[/tex], caused of the tension of the string, equal to [tex]a_c=\omega^2l[/tex], which, in our situation, will be [tex](10.91)^2\times1.1=130.91 m/s^2[/tex]

We're almost done. We got mass, we got acceleration, the tension has to be their product: [tex]T= ma=130.91\times0.15=19.64N[/tex]