Answers:
Starting inequality: [tex]10(x+0.75) \le 50[/tex]
Ending inequality: [tex]x \le 4.25[/tex]
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Work Shown:
x = amount spent per bag, ignoring the bag fee
x+0.75 = amount per bag including bag fee
10(x+0.75) = total amount spent on the ten bags
This amount cannot be more than $50. This means 50 dollars is the highest we can go, aka the ceiling value.
That means we'd write [tex]10(x+0.75) \le 50[/tex] as one possible starting inequality.
Let's solve for x
[tex]10(x+0.75) \le 50\\\\10x+7.5 \le 50\\\\10x \le 50-7.5\\\\10x \le 42.5\\\\x \le 42.5/10\\\\x \le 4.25[/tex]
The most he can spend on the items for any single bag is $4.25, which is ignoring the $0.75 fee
If we tack that fee on, then he spends 4.25+0.75 = 5 dollars per bag and ten of such bags leads to 5*10 = 50 dollars total. The answer is confirmed.
