The amount of current flowing in the wire is 1.69 × 10⁻¹⁶ A
From the question,
We are to calculate, the amount of current flowing in the wire.
From the formula,
[tex]I =\frac{nQ}{t}[/tex]
Where I is the current
n is the number of charge
Q is the quantity of charge
t is the time
From the given information
n = 8
Q = e = 1.69 × 10⁻¹⁹ C
t = 8 msecs = 8 × 10⁻³ sec
Putting the parameters into the formula, we get
[tex]I = \frac{8 \times 1.69 \times 10^{-19} }{8\times 10^{-3} }[/tex]
[tex]I = 1.69 \times 10^{-16} \ A[/tex]
Hence, the amount of current flowing in the wire is 1.69 × 10⁻¹⁶ A
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