Respuesta :

Answer:

yes it can be proved by AAA method for similarity...

Step-by-step explanation:

Given the two triangles, ΔFEG (and its two angles that have measures of 30° and 102°) and ΔNLM  (whose two angles have measures of 48° and 102°).

We can start by using the Angle Angle (AA) criterion, which states that if a triangle has two angles whose measures are equal to the two angles of a second triangle, then those two triangles are similar.  

Since we know that the sum of the interior angles of a triangle is 180°, we can determine the missing angles for Δ FEG and ΔNLM. In doing so, we'll be able to find out if both triangles have two equal angles.  

Find m < G° for Δ FEG:  

m < G° = 180° - 102° - 30°

m < G° = 48°.

Find m < M for ΔNLM:

m< M° = 180° - 102° - 48°

m < M° = 30°.

With our calculations on the measures of the missing angles of each triangle, it turns out that the interior angles of ΔFEG and ΔNLM have the same measures:

< E  = < L  ⇒ 102°

< N = < G  ⇒ 48°

< F = < M  ⇒ 30°  

Therefore, ΔFEG and ΔNLM are similar, as defined by the Angle Angle (AA) criterion.