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A 0.80 kg block rests on a desk. The coefficient of static friction is 0.40. You push the side of the block but do not have a spring scale to measure the force you use. Which statement is true about the force of static friction

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Answer:

It is no larger than 3.1 N.

Lanuel

The force of static friction acting on the block is not larger than 3.316 Newton.

Given the following data:

  • Mass of block = 0.80 kg
  • Coefficient of static friction = 0.40

Acceleration due to gravity = [tex]9.8 \;m/s^2[/tex]

To determine the force of static friction acting on the block:

Mathematically, the force of static friction is given by the formula;

[tex]F_s = uF_n[/tex]

Where;

  • [tex]F_s[/tex] represents the force of static friction.
  • μ represents the coefficient of friction.
  • [tex]F_n[/tex] represents the normal force.

But, [tex]F_n = mg[/tex]

Substituting the value of the normal force, we have:

[tex]F_s =umg\\\\F_s = 0.40 \times 0.80 \times 9.8\\\\F_s = 3.316 \;Newton[/tex]

Therefore, the force of static friction acting on the block is not larger than 3.316 Newton.

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