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Rewrite x2 - 8x + 13 = 0 in the form (x -a)2= b, where a and b are integers, to determine the a and b values.
O a = 4 and b = 3
O a = 3 and b = 2
O a= 2 and b = 1
O a = 1 and b = 4

Respuesta :

Paounn

Answer:

a =4 and b= 3

Step-by-step explanation:

Stare at it for a bit. You have the squre of x, then(ignoring the minus sign) 2 times x times 4. What's left is the square of 4, which is 16; you have 13, you are 3 short. Let's add them to both sides:

[tex]x^2-8x+13+3=3 \rightarrow x^2-8x+16 = 3\\(x-4)^2 = 3[/tex]

so a =4 and b= 3

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