The distance from point (15,-21) to the line 5x + 2y = 4 is 27.5 units
Given the coordinate (15, -21) and the line 5x + 2y = 4
In order to get the point on the line 5x + 2y =4, we can a point on the line
Let x = 0
5(0) + 2y = 4
2y = 4
y = 2
The point (0, 2) is on the line.
Find the distance between the point (15, -21) and (0, 2) using the distance formula
[tex]D=\sqrt{(2+21)^2+(0-15)^2} \\D=\sqrt{23^2+15^2}\\D=\sqrt{754}\\D= 27.46units[/tex]
Hence the distance from point (15,-21) to the line 5x + 2y = 4 is 27.5 units
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