Let's find the value of n ~
- [tex] \dfrac{{6}^{n} }{216} = 6 {}^{7} [/tex]
- [tex] \dfrac{6 {}^{n} }{ {6}^{3} } = 6 {}^{7} [/tex]
- [tex]6 {}^{n} = {6}^{7} \times {6}^{3} [/tex]
- [tex]6 {}^{n} = 6 {}^{7 + 3} [/tex]
- [tex]6 {}^{n} = {6}^{10} [/tex]
Hence , the value of n = 10
