Answer:
40 [adv] and 25 [same-d].
Step-by-step explanation:
1) suppose, the number of advance ticket is 'a', of same-day is 's', then
2) total number of sold ticket is 65, that is: a+s=65 - this is the first equation of system;
3) and the price of the all sold advanced tickets is 35a, the price of the all sold same-day tickets is 20s, then the total price is: 35a+20s=1900 - this is the second equation of system;
4) it is possible to make up and solve the system of two equations:
[tex]\left \{ {{a+s=65} \atop {35a+20s=1900}} \right. \ => \ \left \{ {{4a+4s=260} \atop {7a+4s=380}} \right. \ => \ \left \{ {{a=40} \atop {s=25}} \right.[/tex]
5) finally, 40 advanced and 25 same-day tickets were sold.
