Answer: The constant rate change would be [tex]\frac{1}{9}[/tex].
Step-by-step explanation: The general rate of change can be found by using the difference quotient formula. To find the average rate of change over an interval, enter a function with an interval: f (x) = [tex]x^{2}[/tex] , [2,3]
Write y = [tex]\frac{1}{9}[/tex]x - 20 as a function which is f (x) = [tex]\frac{1}{9}[/tex]x - 20
Consider the difference quotient formula which is [tex]\frac{f (x +h) - f (x) }{h}[/tex].
Find the components of the definition. [tex]\frac{f (x+h) = \frac{h}{9} + \frac{x}{9} - 20}[/tex]simplify then it would be [tex]\frac{f (x) = \frac{x}{9} - 20 }[/tex].
Lastly plug in all the components.
[tex]\frac{f (x + h) - f (x)}{h} = \frac{\frac{h}{9} +\frac{x}{9} - 20 - (\frac{x}{9} - 20) }{h}[/tex]
After solving all this the answer would be [tex]\frac{1}{9}[/tex]
