Answer:
376.56 g/mol.
Explanation:
The molar mass of bromine is approx. 79.904 g/mol. 79.904 x 4 = 319.616 g/mol. The molar mass of Fluorine is approx. 18.998 g/mol. 18.998 x 3 = 56.994 g/mol. 56.994 amu + 319.616 amu = 376.56 g/mol.
Answer:
[tex]\boxed {\boxed {\sf 376.594 \ g/mol}}[/tex]
Explanation:
We are asked to find the molar mass of tetrabromine trifluoride. This compound has the formula Br₄F₃.
The molar mass is the mass of 1 mole of a substance. The values are found on the Periodic Table because they are equal to the atomic masses, but the units are grams per mole instead of atomic mass units.
Look up the molar masses of the individual elements in the compound: bromine and fluorine.
Look at the subscripts in the formula. There is a subscript of 4 after Br and one of 3 after F. This means one mole of the compound contains 4 moles of bromine and 3 moles of fluorine.
Multiply the molar masses by their respective subscript, then add the results.
The molar mass of Br₄F₃ is 376.594 grams per mole.
