Answer:
54.75 mL
Explanation:
First calculate the number of moles of NaCl in the 150mL solution of NaCl
0.0365 moles should be present on 1000cm3 or 1dm3 of water.
1L = 1 dm3
1 mL = 1 / 1000 dm3
150 mL = 150/1000 dm3 = 0.15 dm3
If x moles are present in 0.15 dm3,
x/ 0.15 = 0.0365
We get x= 0.0365 × 0.15 mol
Now x amount of moles should be taken from the initial 0.100 M NaCl solution
So 0.1 moldm-3 = 0.0365× 0.15 mol / V
we get V = 0.05475 dm3
V= 0.05475 L
V= 54.75 mL
