Answer:
[tex]r=2.28*10^8km[/tex]
Step-by-step explanation:
This assumes you were given the mass of mars to be [tex]6.39*10^2^3kg[/tex] the mass of the sun to be [tex]1.99*10^3^0kg[/tex] and the gravitational force between the two to be [tex]3.72*10^3^5N[/tex].
I used the formula: (G is the gravitational constant [tex]6.67*10^-^1^1[/tex])
[tex]F=G\frac{m_1m_2}{r}[/tex]
and solved for r
[tex]3.72*10^3^5=6.67*10^-^1^1\frac{6.39*10^2^3(1.99*10^3^0)}{r}[/tex]
[tex]r=\frac{8.48*10^4^3}{3.72*10^3^5}[/tex]
[tex]r=2.28*10^8km[/tex]
