Answer:
Chemical reaction:
- 2 NO (g) + O₂ (g) → 2 NO₂ (g)
2 moles of NO₂ is produced from O₂ moles = 1
Therefore, 2 moles of NO₂ is produced from O₂ moles = [tex]\dfrac{1}{2} \times 13 = \bf{6.5 mol}[/tex]
For 80 % yield no. of moles of O₂ = 6.5 mol
Then for 100% yield no. of moles of O₂ =[tex] \dfrac{6.5}{80\%} =\dfrac{6.5}{\frac{80}{100}} =\dfrac{6.5}{80} \times 100 = \dfrac{650}{80} = \bf 8.125\;mol [/tex]
