Answer:
Numer of moles of Li₂CO₃:
[tex]\longrightarrow\: n_{(Li_2 CO_3)} = \dfrac{38.5}{(6 \times 2) + 12 + (16 \times 3)}[/tex]
[tex]\longrightarrow\: n_{(Li_2 CO_3)} = \dfrac{38.5}{12+ 12 +48}[/tex]
[tex]\longrightarrow\: n_{(Li_2 CO_3)} = \dfrac{38.5}{72}[/tex]
[tex]\longrightarrow\: n_{(Li_2 CO_3)} = 0.53473 \: mol[/tex]
Chemical Reaction:
2 LiOH(s) + CO₂(g) → Li₂CO₃(s) + H₂O(l)
- 1 mole of Li₂CO₃ is formed from 2 moles of LiOH.
Therefore, applying unitary method:
- 0.53473 mole of Li₂CO₃ is formed from 2 × 0.53473 = 1.06946 moles of LiOH.
