Explanation:
The given equation is in the form [tex]ax^2+bx+c=0[/tex], where,
Use the quadratic formula to get the following
[tex]x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\x = \frac{-(-3)\pm\sqrt{(-3)^2-4(1)(-1)}}{2(1)}\\\\x = \frac{3\pm\sqrt{9+4}}{2}\\\\x = \frac{3\pm\sqrt{13}}{2}\\\\[/tex]
The last equation matches with choice C.