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In a tournament, a professional golfer knows that she is 200 yards from the hole. A spectator is watching her play and is 140 yards away from the golfer.
If the spectator has an angle of 115° between the golfer and the hole, what is the angle that the golfer has between the spectator and the hole?

hole?

25.6°
39.4°
64.3°
65.0°

In a tournament a professional golfer knows that she is 200 yards from the hole A spectator is watching her play and is 140 yards away from the golfer If the sp class=

Respuesta :

Using the law of sines, it is found that the angle that the golfer has between the spectator and the hole is of 25.6º.

What is the law of sines?

Suppose we have a triangle in which:

  • The length of the side opposite to angle A is a.
  • The length of the side opposite to angle B is b.
  • The length of the side opposite to angle C is c.

The lenghts and the sine of the angles are related as follows:

[tex]\frac{\sin{A}}{a} = \frac{\sin{B}}{b} = \frac{\sin{C}}{c}[/tex]

Hence, in this problem, we have that:

[tex]\frac{\sin{115^\circ}}{200} = \frac{sin{x}}{140}[/tex]

[tex]sin{x} = \frac{140\sin{115^\circ}}{200}[/tex]

[tex]x = \arcsin{0.6344}[/tex]

x = 39.4º.

Considering that the sum of the internal angles of the triangle is of 180º, the angle that the golfer has between the spectator and the hole is given by:

A = 180 - (115 + 39.4) = 25.6º.

More can be learned about the law of sines at https://brainly.com/question/27174058

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