Using the vertex, it is found that the maximum height of the punt is of 27.7 feet.
The height of the punt, after x seconds, is given by:
[tex]f(x) = -0.0152x^2 + 1.25x + 2[/tex]
It is a quadratic equation with coefficients [tex]a = -0.0152, b = 1.25, c = 2[/tex].
The maximum value is the value of the function at the vertex, hence:
[tex]f_V = -\frac{\Delta}{4a} = -\frac{b^2 - 4ac}{4a}[/tex]
Applying the coefficients:
[tex]f_V = -\frac{b^2 - 4ac}{4a} = -\frac{(1.25)^2 - 4(-0.0152)(2)}{4(-0.0152)} = 27.7[/tex]
The maximum height of the punt is of 27.7 feet.
A similar problem is given at https://brainly.com/question/16858635
