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A system releases 622 kJ of heat and does 105 kJ of work on the surroundings. What is the change in internal energy of the system

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OCcommonkings

Answer:

Δ-727 or -7.27x10²kJ

Explanation:

ΔV=q-w

(q)= -622

(w)= -105

(both negative because it indicate loss of energy)

ΔV= -622+(-105)

ΔV= -727 kJ

asuwafohjames

The change in internal energy of the system when it released a heat of 622 kJ and does a work of 105 kJ on the surroundings is -727 kJ.

What is change in internal energy?

Internal energy is all the energy contained in an object.

To calculate the change in internal energy of the system, we use the formula below.

Formula:

  • ΔU = Q-W............. Equation 1

Where:

  • ΔU = Change in internal energy of the system,
  • W = work done by the system
  • Q = Heat released by the system.

From the question,

Given:

  • Q = - 622 kJ ( released of heat)
  • W = 105 kJ.

Substitute these values into equation 1

  • ΔU = -622-105
  • ΔU = -727 kJ

Hence, the change in internal energy of the system when it released a heat of 622 kJ and does a work of 105 kJ on the surroundings is -727 kJ.

Learn more about internal energy here: https://brainly.com/question/25737117

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