Answer:
(1,0)
Step-by-step explanation:
Hi there!
We want to find the x intercept of the line that passes through the point (3,4) and has a slope of 2
First, let's find the line
We are given both a slope, and a point. We can write the equation of the line in point-slope form, which is [tex]y-y_1=m(x-x_1)[/tex], where m is the slope and [tex](x_1, y_1)[/tex] is a point
We do have everything needed to write the equation, let's just label everything to avoid confusion:
m=2
[tex]x_1=3[/tex]
[tex]y_1[/tex]=4
Now substitute those values as the variables that they represent into the equation:
[tex]y-y_1=m(x-x_1)[/tex]
y-4=2(x-3)
Now we have the equation in slope-point form
The x intercept of the line is the value in which the line passes through the x axis. The value of y at this point is 0
So we can substitute y as 0 in the equation to find out the value of x:
y-4=2(x-3)
0-4=2(x-3)
Multiply
0-4=2x-6
Add 6 to both sides
0+2=2x
Simplify the left
2=2x
Divide both sides by 2
1=x
So the value of the x intercept is 1, also written as the point (1,0)
Hope this helps!
