please help me with this question as it's really important
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Answer:
(i)
A → CH3CH2CH3 ( Propane )
B → CH3CH(Cl)CH3 ( 2-Chloropropane )
C → No product
D→ CH3CH=CH2 ( 2-propene )
E → CH3CH2COOH ( Propanoic acid )
(ii)
Reagent X → Acidified water [ H+ / H2O ]
Reagent Y → Bromine with Carbon tetrachloride [ Br2 / CCl4 ]
Reagent Z → Sodium hydroxide [NaOH]