Let's check Electronic configuration of N in ground state
[tex]\\ \sf\longmapsto 1s^22s^22p^3[/tex]
[tex]\\ \sf\longmapsto 1s^22s^22px^12py^12pz^2[/tex]
In hydrogen case
[tex]\\ \sf\longmapsto 1s^1[/tex]
Hence Hybridization
[tex]\\ \sf\longmapsto s-p-p-p[/tex]
[tex]\\ \sf\longmapsto sp^3[/tex]
Structure is tetrahedral .
Spare way:-
- Bond pairs==3=>Bonding electrons=6
- Lone pair=1=>Anti bonding electrons=2
Hybridization
[tex]\\ \sf\longmapsto \dfrac{1}{2}[\sigma+\sigma *][/tex]
[tex]\\ \sf\longmapsto \dfrac{1}{2}[6+2][/tex]
[tex]\\ \sf\longmapsto \dfrac{1}{2}[8][/tex]
[tex]\\ \sf\longmapsto 4[/tex]
- sp3 Hybridization
- Shape-Tetrahedral .
