6. A 10.0 g sample of krypton has a temperature
of 25 °C at 575 mmHg. What is the volume, in
milliliters, of the krypton gas?

Respuesta :

Considering the definition of ideal gas law, the volume of the Krypton gas is 3840 mL.

An ideal gas is a theoretical gas that is considered to be composed of point particles that move randomly and do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.

The pressure, P, the temperature, T, and the volume, V, of an ideal gas, are related by a simple formula called the ideal gas law:  

P×V = n×R×T

where P is the gas pressure, V is the volume that occupies, T is its temperature, R is the ideal gas constant, and n is the number of moles of the gas. The universal constant of ideal gases R has the same value for all gaseous substances.

Now, taking into account this law, and isolating the pressure variable (P), you get:

[tex]V=\frac{nxRxT}{P}[/tex]

In this case, you know:

  • n= [tex]10 gramsx\frac{1 mole}{83.80 grams} =[/tex]0.119 moles, where 83.80[tex]\frac{grams}{mole}[/tex] is the molar mass of Krypton, that is, the amount of mass that a substance contains in one mole.
  • R= 0.082 [tex]\frac{atmL}{moleK}[/tex]
  • T= 25 C=298 k
  • P= 575 mmHg=0.756579 atm (being 1 atm=760 mmHg)

Replacing in the ideal gas law:

[tex]V=\frac{0.119 molesx0.082 \frac{atmL}{moleK}x298K}{0.756579 atm}[/tex]

Solving:

V=3.84 L= 3840 mL (being 1 L=1000 mL)

Finally, the volume of the Krypton gas is 3840 mL.

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